a^2(b-c)-b^2(a+c)-c^2(a-b)+2abc=0

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Solution for a^2(b-c)-b^2(a+c)-c^2(a-b)+2abc=0 equation: 


Simplifying
a2(b + -1c) + -1b2(a + c) + -1c2(a + -1b) + 2abc = 0
(b * a2 + -1c * a2) + -1b2(a + c) + -1c2(a + -1b) + 2abc = 0
(a2b + -1a2c) + -1b2(a + c) + -1c2(a + -1b) + 2abc = 0
a2b + -1a2c + (a * -1b2 + c * -1b2) + -1c2(a + -1b) + 2abc = 0
a2b + -1a2c + (-1ab2 + -1b2c) + -1c2(a + -1b) + 2abc = 0
a2b + -1a2c + -1ab2 + -1b2c + (a * -1c2 + -1b * -1c2) + 2abc = 0
a2b + -1a2c + -1ab2 + -1b2c + (-1ac2 + 1bc2) + 2abc = 0

Reorder the terms:
2abc + -1ab2 + -1ac2 + a2b + -1a2c + 1bc2 + -1b2c = 0

Solving
2abc + -1ab2 + -1ac2 + a2b + -1a2c + 1bc2 + -1b2c = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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